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ATQ, Total sum of 8 consecutive odd numbers = 20 X 8 = 160 According to Arithmetic progression: Sum = n/2[2a+(n-1)×d] [where n = number of terms, 'a' = irst term and 'd' = common dierence] Or, 160 = 8/2[2a+(8-1)×2] Or, 40 = 2a + 7 × 2 Or, 26 = 2a So, 'a' = 13 Last number = a + (n - 1) × d = 13 + (8 - 1) × 2 = 27 Previous odd number to these numbers = 13 - 2 = 11 And, next odd number to these numbers = 27 + 2 = 29 So, required average = (160+11+29)/10 = 200 ÷ 10 = 20 Alternate Solution Since, the number that are included is equally more and less than sum of the given 8 numbers, therefore, there eect will cancel out and the average will remain sum.
If 10 9 38 x 5428
Then, 2x² + 1 = ?
...13 24 75 134 447 892
...11 33 66 112 173 ? .
3 5 7 25 8...
The series given below contains a sequence of numbers. Accordingly identify the incorrect number.
85, 84, 81, 88, 77, 92, 72
40 41 86 ? 1084 5445
...12 11 21 62 ? 1234
Direction: Which of the following will replace ‘?’ in the given question?
10, 12, ‘?’, 27, 36, 45, 54, 63, 72
112 162 199 ? 242 252
...6 16 116 566 2272 6814
11 a�...