Question
If a:b:c = 3:4:6, and (5a + 3c) = 132, then find the
value of '3b'.Solution
ATQ, Let a = '3p' So, b = 3p × (4/3) = '4p' And c = 3p × (6/3) = '6p' ATQ; 3p × 5 + 6p × 3 = 132 Or, 15p + 18p = 132 So, 33p = 132 So, p = 4 So, required value = 4 × 4p = 4 × 3 × 4 = 48
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