Question
Consider three positive numbers that form a ratio of
2:3:4. If the sum of the squares of these numbers is 2349, what is the average of the largest and the second largest numbers?Solution
Let the three numbers be 2x, 3x and 4x, respectively. ATQ; (2x) 2 + (3x) 2 + (4x) 2 = 2349 Or, 4x2 + 9x2 + 16x2 = 2349 Or, 29x2 = 2349 Or, x2 = 81 So, x = 9 (Since, numbers are positive therefore we can discard the negative root) So, required average = {(3 x 9) + (4 x 9)} ÷ 2 = (63/2) = 31.5 Hence, option c.
19.89% of 449.67 + 14.67% of 299.89 - 9.89% of 99.79 = ?
`(sqrt(960.87)xx9.932+sqrt(629.998)xx26.385)/(sqrt(1028.902)xx4.977)=?`
Find the approximate value of Question mark(?). There is no requirement to find the exact value.
? = 200.14 + 27.98 × 16.05 − (10.03)² - 12.9...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
1299.999 ÷ 325.018 × 24.996 = ?
What approximate value should replace the question mark?
99.95 − √529 × 3 + 1439.80 ÷ 12.02 = ?
619.97 ÷ 20.01 X 124.99 ÷ 24.91 = ?
124% of 620.99 + 11.65% of 1279.23 = ?
What approximate value should replace the question mark?
9.96% of 1200.10 − 25% of 4800 = ? − 7000.20
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