Question
Consider six consecutive odd numbers whose average is
34. If the highest number from this set is removed, what will be the average of the remaining five numbers?Solution
Let six consecutive odd numbers be ‘x’, ‘x + 2’, ‘x + 4’, ‘x + 6’, ‘x + 8’, ‘x + 10’, respectively. ATQ; (x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10) = 34 × 6 Or, 6x + 30 = 204 Or, 6x = 174 Or, x = 29 When, the greatest number is excluded, Then, new sum of the remaining five numbers = x + x + 2 + x + 4 + x + 6 + x + 8 = 5x + 20 Required Average = {(5x + 20)/5} = (x + 4) = 29 + 4 = 33
Currently, Person 'A' is 42 years old. Person 'B' is 6 years younger than 'A'. Three years ago, the age of 'C' was 25% less than what 'B' is right now. ...
The present age of A is 5/3 times to that of his marriage age. Present age of his brother is 1/3rd of his present age. If A was married 36 years ago the...
The ratio of the present ages of ‘A’ and ‘B’ is 5:6, respectively. Three years hence from now, the age of ‘B’ will be 21 years. If the avera...
A student multiplied a number by 4/5 instead of 5/4. What is the percentage error in the calculation.
The present age of Surjeet and Rakesh are in the ratio of 4:5. After 8 years the ratio of their ages will be 6:7. What is 70% of the sum of their presen...
- The ratio of the age of R after 3 years to the age of S after 6 years is 3:2. The total age of S and T after 10 years is 84 years. T’s age 6 years ago wa...
20 years ago, the age of ‘I’ was 50% more than ‘J’. If the sum of their present ages is 90 years, then find the present age of ‘I’.
...A boy’s age is 125% of what it was 8 years ago, but 75% of what it will be after 8 years. What is his present age?
The sum of the present ages of a father and his daughter is 80 years. Eight years ago, the father’s age was seven times the age of his daughter. Eight...
- Ankit is 3 years younger than Rohit while Rohit is 5 years younger than Suman. If 5 years from now, the ratio of the age of Ankit and Suman will be 3:4 res...
Relevant for Exams:
