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    Question

    Consider six consecutive odd numbers whose average is

    34. If the highest number from this set is removed, what will be the average of the remaining five numbers?
    A 33 Correct Answer Incorrect Answer
    B 35 Correct Answer Incorrect Answer
    C 38 Correct Answer Incorrect Answer
    D 36 Correct Answer Incorrect Answer

    Solution

    Let six consecutive odd numbers be тАШxтАЩ, тАШx + 2тАЩ, тАШx + 4тАЩ, тАШx + 6тАЩ, тАШx + 8тАЩ, тАШx + 10тАЩ, respectively. ATQ; (x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10) = 34 ├Ч 6 Or, 6x + 30 = 204 Or, 6x = 174 Or, x = 29 When, the greatest number is excluded, Then, new sum of the remaining five numbers = x + x + 2 + x + 4 + x + 6 + x + 8 = 5x + 20 Required Average = {(5x + 20)/5} = (x + 4) = 29 + 4 = 33

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