Four persons ‘A’, ‘B’, ‘C’, and ‘D’ have different amounts with them. ‘D’ has twice the amount than that of ‘A’. The amount ‘B’ has is 12.5% more than that of ‘D’. The amount ‘C’ has is equal to the average amount all four people have. If the sum of the average amount all four have and the amount ‘A’ has is Rs. 1100, then find the amount ‘D’ has.
Let ‘A’ has Rs. a Therefore, amount possessed by ‘D’ = Rs. 2a Amount possessed by ‘B’ = 1.125 × 2a = Rs. 2.25a Let the average amount possessed by all four be Rs. x Therefore, amount possessed by ‘C’ = Rs. x According to the question, 2.25a + 2a + a = 4x – x Or, 5.25a = 3x Or x/a = 7/4 Therefore, a = 1100 × 4/11 = Rs. 400 Amount possessed by ‘D’ = 2a = Rs. 800.
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