Question
Four persons ‘A’, ‘B’, ‘C’, and ‘D’ have
different amounts with them. ‘D’ has twice the amount than that of ‘A’. The amount ‘B’ has is 12.5% more than that of ‘D’. The amount ‘C’ has is equal to the average amount all four people have. If the sum of the average amount all four have and the amount ‘A’ has is Rs. 1100, then find the amount ‘D’ has.Solution
Let ‘A’ has Rs. a Therefore, amount possessed by ‘D’ = Rs. 2a Amount possessed by ‘B’ = 1.125 × 2a = Rs. 2.25a Let the average amount possessed by all four be Rs. x Therefore, amount possessed by ‘C’ = Rs. x According to the question, 2.25a + 2a + a = 4x – x Or, 5.25a = 3x Or x/a = 7/4 Therefore, a = 1100 × 4/11 = Rs. 400 Amount possessed by ‘D’ = 2a = Rs. 800.
19.89% of 449.67 + 14.67% of 299.89 - 9.89% of 99.79 = ?
`(sqrt(960.87)xx9.932+sqrt(629.998)xx26.385)/(sqrt(1028.902)xx4.977)=?`
Find the approximate value of Question mark(?). There is no requirement to find the exact value.
? = 200.14 + 27.98 × 16.05 − (10.03)² - 12.9...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
1299.999 ÷ 325.018 × 24.996 = ?
What approximate value should replace the question mark?
99.95 − √529 × 3 + 1439.80 ÷ 12.02 = ?
619.97 ÷ 20.01 X 124.99 ÷ 24.91 = ?
124% of 620.99 + 11.65% of 1279.23 = ?
What approximate value should replace the question mark?
9.96% of 1200.10 − 25% of 4800 = ? − 7000.20
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