Question
If average of first 10 numbers is (n β 46) and the sum
of remaining number is 1850. Find the value of βnβ, if the average of 20 numbers is βnβ.ΒSolution
According to the question, => 20n = 10 ΓΒ (n β 46) + 1850 => 20n - 10n = 1850 β 460 => n = 139
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