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      Question

      A cricketer whose bowling average is 28.25 runs per

      wicket takes 2 wickets for 73 runs and thereby increases his average by 0.75. The number of wickets taken by him before the last match was;
      A 40 Correct Answer Incorrect Answer
      B 32 Correct Answer Incorrect Answer
      C 20 Correct Answer Incorrect Answer
      D 46 Correct Answer Incorrect Answer
      E None of these Correct Answer Incorrect Answer

      Solution

      Let the no. of wickets taken before the last match be n. Total runs at 28.25 runs per wickets = 28.25n Total runs after the current match = 28.25n + 73 Total no. of wickets after the current match = n + 2 Bowling average after the current match ⇒ (28.25n + 73 )/(n + 2) = 28.25 + 0.75 ⇒( 28.25n + 73 )/ (n + 2) = 29 Or, 28.25n + 73 = 29n + 58 Or, 0.75n = 73-58 Or, n = 15/.75 = 20

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