Question
A cricketer whose bowling average is 28.25 runs per
wicket takes 2 wickets for 73 runs and thereby increases his average by 0.75. The number of wickets taken by him before the last match was;Solution
Let the no. of wickets taken before the last match be n. Total runs at 28.25 runs per wickets = 28.25n Total runs after the current match = 28.25n + 73 Total no. of wickets after the current match = n + 2 Bowling average after the current match ⇒ (28.25n + 73 )/(n + 2) = 28.25 + 0.75 ⇒( 28.25n + 73 )/ (n + 2) = 29 Or, 28.25n + 73 = 29n + 58 Or, 0.75n = 73-58 Or, n = 15/.75 = 20
Simplify the following trigonometric expression:
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12 cos 68o cosec 22o - 3 cot 72o cot 18o- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
√65 of 14.97 + √50 = (12.02)2 - ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
181.87 ÷ 13.89 X 8.13 + ? = 11.852Â
`[(7.99)^2 - (13.001)^2 + (4.01)^3]^2=` ?
(24.88% of 4879.79) + 20.030 × 13.88 of 13.86 + 46.21 = ? + (13.22)²
(8.86)² × (15.01)² ÷ √624.99 = 9?
What approximate value should come in the place of (?) in the following questions?
42.98% of 849 + 18.45% of 1201 ≈ ?
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