Question
The average weight of 4 persons is 44 kg. The heaviest
person’s weight is 30 kg more than the lightest person’s weight. If the average weight of the rest two persons is 48 kg, then find the weight of the heaviest person.Solution
The sum of the weight of 4 persons = 44 × 4 = 176 kg Let the weight of the lightest person = ‘x’ kg The weight of the heaviest person = (x + 30) kg The sum of the weight of the remaining two persons = 48 × 2 = 96 kg According to the question, x + x + 30 + 96 = 176 2x = 50 x = 25 The weight of the heaviest person = 25 + 30 = 55 kg
(m - 4) 2 + (n + 5) 2 + (p - 3) 2 = 0, then find the value of 2m + 3n - p.
If x + y + z = 6, and x3 + y3 + z3 = 36, xyz = 6 then find (xy +yz + zx)?
(x – 4)2 + (y + 3) 2 + (z – 5) 2 = 0, then find the value of 2x + 3y – z.
The roots of the quadratic equation x² + px + q = 0 are in the ratio 3:4. If the sum and product of the roots are 7 and 12, respectively, find the valu...
If the length of a rectangle is increased by 40%, and the breadth is decreased by 20%,then the area of the rectangle increases by x%. Then the value of ...

If 1/(x+ 1/(y+ 1/z)) = 13/30, then find x+y+z= ?
What is the HCF of (x³ + 3x² - x - 3) and (x³ + 4x² + x - 6)?
Length of each side of a rhombus is 13 cm and one of the diagonal is 24 cm. What is the area (in cm2) of the rhombus?
The length of a rectangle is four times its breadth. If its length is increased by 20 cm and breadth is increased by 20 cm, the area of the rectangle is...