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Let the average weight of all five = 100x So, weight of P = 80x, Q = 102x and R = 84x Let the weight of S = a and that of T = b =>(80x + 102x + 84x + a + b)/5 = 100x => a + b = 234x => a : b = 5:8 → a = (5/13) × 234 = 90x → b = (8/13) × 234 = 144x Difference = 144x – 90x = 54x => 54x = 67.5 => x = (67.5/54) = 1.25 Average weight of all the five persons = 100 × 1.25 = 125 kg
24.75% of 639.87 + (299.98 ÷ 2.5) = ?2 + 24.18
2380.03 ÷ 84.98 x 39.9 = ? + 15.32
? = 650.24 + 1124.97 – 14.992
(9.013 – 15.04) = ? + 7.98% of 5199.98
A bag contains 25 white and some black balls. If the probability of drawing a black ball from the bag is thrice that of drawing a white ball, fin...
25.902 × 78.095 + 999.996% of 200.08 + 20.005 % of 7999.997 = ? × 15.008 × 33.009
[{(√785) % of 449.85}/(35.89 × 7.14 + 849.89 ÷ 5.12 + 199.78% of 41.09)] = ( 1/? )
√1567.763`xx` √4400 ÷ 326.9827 + 1223.293 = ?