Start learning 50% faster. Sign in now
Let the capacity of the cistern = 60 units Then, efficiency of pipe ‘A’ = 60/20 = 3 units/minute Efficiency of pipe ‘B’ = 60/15 = 4 units/minute Efficiency of pipe ‘C’ = 60/12 = 5 units/minute So, combined efficiency of pipes ‘A’, ‘B’ and ‘C’ = 3 + 4 – 5 = 2 units/minute 50% of the cistern’s capacity = 30 units Therefore, time taken by all 3 pipes together to fill 50% of the cistern = 30/2 = 15 minutes
Four terms are in proportion. The first, second and fourth terms are 4, 22, and 33. Find the third term.
3 2 2 3 8 ?
...31 33 69 212 ? 4286
...1 2 6 ...
13, 14, 18, 27, 43, ?
104 136 152 160 164 ?
...4 7 24 91 462 2763
18 ...
123 125 129 132 ? 145
42 43 46 ...
2342 2223 2090 1943 1782 ?
...