Question
Solve the given equation for ?. Find the approximate
value. [(9/10 of 449.88) - (30% of 299.78)] Γ [(β120.91 Γ· 11) + (1/3 of 600.11)] = ?Solution
[(9/10 of 449.88) - (30% of 299.78)] Γ [(β120.91 Γ· 11) + (1/3 of 600.11)] = [(9/10 of 450) - (30% of 300)] Γ [(β121 Γ· 11) + (1/3 of 600)] = [(0.9 Γ 450) - (0.3 Γ 300)] Γ [(11 Γ· 11) + (1/3 Γ 600)] = (405 - 90) Γ [1 + 200] = 315 Γ 201 = 63315 Answer: C
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