Question
Solve the given equation for ?. Find the approximate
value. [(9/10 of 449.88) - (30% of 299.78)] × [(√120.91 ÷ 11) + (1/3 of 600.11)] = ?Solution
[(9/10 of 449.88) - (30% of 299.78)] × [(√120.91 ÷ 11) + (1/3 of 600.11)] = [(9/10 of 450) - (30% of 300)] × [(√121 ÷ 11) + (1/3 of 600)] = [(0.9 × 450) - (0.3 × 300)] × [(11 ÷ 11) + (1/3 × 600)] = (405 - 90) × [1 + 200] = 315 × 201 = 63315 Answer: C
20% of 1500 – 75% of 200 = 125% of ?Â
24% of 150% of 500 + 140 = ? × 8Â
458.32 - 563.32 + 659.32 =?
What will come in the place of question mark (?) in the given expression?
(√1089 + 84 ÷ 2) % of 348 = 416 - ?
40% are the passing marks. A student gets 250 marks yet fails by 38 marks. What is the maximum marks?
(22.5 × 24) ÷ 40 + 51.50 = ? ÷ 5.25
36×?² + (25% of 208 +13) = 60% of 2400 + 17×18
What will come in the place of question mark (?) in the given expression?
√64 X 9 ÷ 3 + 12 X 3 = ? + 36(3/7) x 868 + 25% of 240 = (? + 65)
