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    Question

    Solve the given equation for ?. Find the approximate

    value. [(9/10 of 449.88) - (30% of 299.78)] ├Ч [(тИЪ120.91 ├╖ 11) + (1/3 of 600.11)] = ?
    A 61825 Correct Answer Incorrect Answer
    B 62775 Correct Answer Incorrect Answer
    C 63315 Correct Answer Incorrect Answer
    D 64285 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    [(9/10 of 449.88) - (30% of 299.78)] ├Ч [(тИЪ120.91 ├╖ 11) + (1/3 of 600.11)] = [(9/10 of 450) - (30% of 300)] ├Ч [(тИЪ121 ├╖ 11) + (1/3 of 600)] = [(0.9 ├Ч 450) - (0.3 ├Ч 300)] ├Ч [(11 ├╖ 11) + (1/3 ├Ч 600)] = (405 - 90) ├Ч [1 + 200] = 315 ├Ч 201 = 63315 Answer: C

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