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Given: (1/6) :(1/8) :(1/5)
Multiplying throughout by 120 (LCM of 6, 8 and 5) , we get
So, a:b:c = 20:15:24
Let 'a' = '20x', 'b' = '15x' and 'c' = '24x'
So, 20x + 15x + 24x = 236
So, 59x = 236
So, x = 4
So, required value = 24x - 20x = 4x = 4 X 4 = 16
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