Question
If sinA = 3/5 and cosB = 12/13, where A and B are in the
first quadrant, find sin(A + B).Solution
We know sin(A + B) = sinA * cosB + cosA * sinB. Given sinA = 3/5, cosA = √(1 - sin²A) = √(1 - (3/5)²) = √(1 - 9/25) = √(16/25) = 4/5. Also, cosB = 12/13, so sinB = √(1 - cos²B) = √(1 - (12/13)²) = √(1 - 144/169) = √(25/169) = 5/13. Now, sin(A + B) = (3/5)(12/13) + (4/5)(5/13) = 36/65 + 20/65 = 56/65.
- Which major resource was launched during ISHTA 2025 to aid TB diagnosis?
What is the primary goal of the "Ek Pedh Maa Ke Naam" plantation drive?
What is the key requirement for foreign universities to set up and operate their campuses in India, as per the UGC regulations?
Who is the Indian Envoy to Denmark?
Recently President Joe Biden announced that the US is nominating whom to lead the World Bank?
On 12th November every year which of the following day is observed?
Which government has recently decided to provide reservation in medical colleges for students from government schools?
What is the total area covered by Pobitora Wildlife Sanctuary in Assam?
Which organization has been roped in for the training of Anganwadi workers to implement Early Childhood Care and Education (ECCE) under the Centre's fla...
Where is the 16th BRICS Summit 2024 organized?
Relevant for Exams:
