Question
In a jar initially containing 'm' liters of pure milk
costing Rs. 20 per liter, 50% of the milk is taken out, and honey is added to the remaining milk. This mixture is then poured into another jar, which already contains the same quantity, with a mixture of milk and honey in a ratio of 3:1. To make a 10% profit, find the selling price per liter of this final mixture.ÂSolution
ATQ, First jar ‘m’ liter of pure milk. 50 percent taken out and honey added. So Milk = 0.5m; Honey = 0.5m Second container: same quantity m. Milk: Honey = 3: 1. So Milk= 0.75m and honey = 0.25m Two containers mixed: Total = 2m; Milk = 1.25m and Honey = 0.75m Cost price = Rs.20 Total quantity = By mixture method, let 'n' be the actual price of the mixture and given cost price of milk is 20 and honey is 0 (20 – n)/(n – 0) = 0.75/1.25 n = 12.5; Selling price with 10% profit = 1.1 × 12.5 = 13.75 rupees per liters
Evaluate:
√729 + √49 - √16 + 1/√64
Simplify:

(1/5)(40% of 800 – 120) = ? × 5
2/5 of 3/4 of 7/9 of 7200 = ?
`sqrt(5476)` + 40% of 1640 = ? `xx` 4 - 2020
? = (22% of 25% of 60% of 3000) + 21
Determine the simplified value of the given mathematical expression.
(342 – 20% of 5280) = ? ÷ 3
∛157464 =?