Question
In a jar initially containing 'm' liters of pure milk
costing Rs. 20 per liter, 50% of the milk is taken out, and honey is added to the remaining milk. This mixture is then poured into another jar, which already contains the same quantity, with a mixture of milk and honey in a ratio of 3:1. To make a 10% profit, find the selling price per liter of this final mixture.ÂSolution
ATQ, First jar ‘m’ liter of pure milk. 50 percent taken out and honey added. So Milk = 0.5m; Honey = 0.5m Second container: same quantity m. Milk: Honey = 3: 1. So Milk= 0.75m and honey = 0.25m Two containers mixed: Total = 2m; Milk = 1.25m and Honey = 0.75m Cost price = Rs.20 Total quantity = By mixture method, let 'n' be the actual price of the mixture and given cost price of milk is 20 and honey is 0 
(20 – n)/(n – 0) = 0.75/1.25 n = 12.5; Selling price with 10% profit = 1.1 × 12.5 = 13.75 rupees per liters
Statements: M % C & G @ T $ D; W % M # PÂ
Conclusions :Â Â Â Â Â I. D % CÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. M % GÂ Â Â Â Â Â Â Â Â Â Â Â Â ...
Statements: G > N > P = E ≥ H < L; M < E < B < C = Q > X; U > W > Y = Q > H
Conclusions:
I). U > P
II). Y > P
...Statements: A > B; C > D; E ≥ A; F = C; C < B
Conclusions:
(i) B > D (ii) A > F (iii) F < E
...Which of the following symbols should replace the question mark in the given statement in order to make conclusion 'B>Z' as well as 'C>X' definitely tr...
Statements: F % W, W © R, R @ M, M $ D
Conclusions:
 I.D @ R                               II.M $ F�...
Statements: H > S ≥ F = B ≤ U≤ T; E ≤ B ≤ K
Conclusions:I. K > F II. K = F
Statements:  B > K < Y, E > C ≥ O = Y
Conclusions:
I. C > B
II. E ≤ Y
III. E > K
IV. O ≥ K
...Statements: B > D = C ≥ E ≥ G, C = H ≤ I < F
Conclusions:
I. B > H
II. I ≥ G
III. F > DStatement: E < F ≤ G = H, I ≥ G ≤ J ≤ K
Conclusion: I. K > EÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. H > K
...Statement: W>Y<X<Z=U>S; W<T ≥V
I. Y<T
II. X > V
Relevant for Exams:
