📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!

    Question

    If ab + bc + ca = 0 Find the value of

    1/(a2 - bc) + 1/(b2 - ca) + 1/(c2 - ab)
    A 2 Correct Answer Incorrect Answer
    B -1 Correct Answer Incorrect Answer
    D 1 Correct Answer Incorrect Answer

    Solution

    ab + bc + ca = 0 bc = - ab – ca ca = - ab – bc ab = -bc –ca Now, 1/(a2 - bc) + 1/(b2 - ca) + 1/(c2 - ab) = 1/(a2 - (-ab - ca)) + 1/(b2 - (-ab - bc)) + 1/(c2 - (-bc-ca)) =1/(a2 + ab+ca) + 1/(b2 + ab+bc) + 1/(c2 + bc+ca) = 1/(a(a + b + c)) + 1/(b(a + b + c)) + 1/(c(a + b + c)) = (bc + ca + ab)/(abc(a + b + c)) = 0/(abc(a + b + c)) = 0

    Practice Next
    More Algebra Questions

    Relevant for Exams:

    ask-question