If ab + bc + ca = 0
Find the value of 1/(a2 - bc) + 1/(b2 - ca) + 1/(c2 - ab)
ab + bc + ca = 0 bc = - ab – ca ca = - ab – bc ab = -bc –ca Now, 1/(a2 - bc) + 1/(b2 - ca) + 1/(c2 - ab) = 1/(a2 - (-ab - ca)) + 1/(b2 - (-ab - bc)) + 1/(c2 - (-bc-ca)) =1/(a2 + ab+ca) + 1/(b2 + ab+bc) + 1/(c2 + bc+ca) = 1/(a(a + b + c)) + 1/(b(a + b + c)) + 1/(c(a + b + c)) = (bc + ca + ab)/(abc(a + b + c)) = 0/(abc(a + b + c)) = 0
Statements:Q ≥ R,R < S,S < T
Conclusions: I. T > R II. Q ≥ T
Statement: E < F ≤ G = H, I ≥ G ≤ J ≤ K
Conclusion: I. K > E II. H > K
...Which of the following symbols should replace the question mark in the given statement in order to make conclusion 'L > G' as well as 'B > X' definitel...
Statements:
M > N = W; J < P = N; Y > P
Conclusions:
I. Y > W
II. M < Y
III. J > M
Statements: Q > R ≥ V = U ≤ W > S = T ≤ X
Conclusion
I: X ≤ V
II: X > V
Statements: M ≤ N; O < R; O = N; S ≥ Q; N > S
Conclusions:
(i) Q < M
(ii) N ≥ Q
(iii) M > R
Statements: J ≤ K = L ≤ N; N ≤ O = M
Conclusions: I. M = J II. J < M
...Statements: T # L # C $ X & Y % E % F
Conclusions:
I. Y @ F
II. Y & F
III. Y & C
...Statements: V = W ≤ X > R ≥ O; C < O; F = X
Conclusion: I. F > R II. X > C
Statements: A % B & Z % B; B # C & E; E @ P # D
Conclusions : I. C @ P II. A % P ...
