Question
If x, y and z are real numbers such that
(x-5)2+(y-8)2+(z-12)2= 0 then (x+y+z) is equal toSolution
if a2+b2+c2 +...so on = 0 then a=b=c=....so on = 0 So ATQ, x-5=0, y-8=0 and z-12=0 So x=5, y =8 and z= 12 hence x+y+z =5+8+12 =25 ` `
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