Question
If 'x' is the lowest positive integer divisible by 8,
12 and 20, then find the second smallest positive integer which is divisible by all the three given numbers?Solution
Lowest positive integer divisible by 8, 12 and 20 = LCM (8, 12, 20) So, LCM of (8, 12, and 20) = 2³ × 3¹ × 5¹ = 120 Therefore, the next larger number which is divisible by all the three given numbers = 2 × 120 = 240
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