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    Question

    If 'x' is the lowest positive integer divisible by 8,

    12 and 20, then find the second smallest positive integer which is divisible by all the three given numbers?
    A 240 Correct Answer Incorrect Answer
    B 360 Correct Answer Incorrect Answer
    C 480 Correct Answer Incorrect Answer
    D 600 Correct Answer Incorrect Answer

    Solution

    Lowest positive integer divisible by 8, 12 and 20 = LCM (8, 12, 20) So, LCM of (8, 12, and 20) = 2Âł Ă— 3Âą Ă— 5Âą = 120 Therefore, the next larger number which is divisible by all the three given numbers = 2 Ă— 120 = 240

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