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    Question

    (x тАУ 4)2 + (y + 3) 2 + (z тАУ

    5) 2 = 0, then find the value of 2x + 3y тАУ z.
    A -6 Correct Answer Incorrect Answer
    B 6 Correct Answer Incorrect Answer
    C 12 Correct Answer Incorrect Answer
    D 18 Correct Answer Incorrect Answer

    Solution

    If (x тАУ 4)2 + (y + 3) 2 + (z тАУ 5) 2 = 0, then (x = 4), (y = -3), and (z = 5).

    So,
    - x - 4 = 0 тЖТ x = 4
    - y + 3 = 0 тЖТ y = -3
    - z - 5 = 0 тЖТ z = 5

    Therefore, required value:
    2(4) + 3(-3) - 5 = 8 тАУ 9 ┬атАУ 5 ┬а= -6

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