Question
(x – 4)2 + (y + 3) 2 + (z –
5) 2 = 0, then find the value of 2x + 3y – z.Solution
If (x – 4)2 + (y + 3) 2 + (z – 5) 2 = 0, then (x = 4), (y = -3), and (z = 5).
So,
- x - 4 = 0 → x = 4
- y + 3 = 0 → y = -3
- z - 5 = 0 → z = 5
Therefore, required value:
2(4) + 3(-3) - 5 = 8 – 9 – 5 = -6
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