Question
If 112 ÷28 x 22 –12 x 6 ÷ 3 +12 = z, then
find the value of z.Solution
112 ÷28 x 22 –12 x 6 ÷ 3 +12 = z 4 x 22 –12 x 2 +12 = z 4 x 22 –12 x 2 +12 = z 16-24+12=z Z=4.
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