Question
If 6y² – 13y + 6 = 0, then find the sum of the two
roots of the equation.Solution
6y² – 13y + 6=0 6y² – 4y-9y+6=0 2y(3y-2)-3(3y-2) =0 (2y-3) (3y-2) =0 When 2y-3=0 Y=3/2 And 3y-2=0 Then y=2/3 Product of roots =3/2+2/3 =13/6 Â
The average of three numbers a, b and c is 2 more than c. The average of a and b is 48. If d is 10 less than c, then the average of c and d is:
If the sum of three numbers is zero, then which of the options below will always be equal to the value of the sum of the cubes of those numbers?
If  x = 19 , find x 5 - 20  x 4 + 20  x 3 - 20x 2 + 20x  - 20 = ?
Given that x8-34x4+1=0, x>0. What is the value of (x3+ x-3)?

If x2a = y2b =z2c ≠ 0 and x2 = yz, then the value of (ab + bc + ca) /bc is :
when x =4 and y =-6 then find the value of 27x³ +58x²y +31xy² +8y³?
Given that x = 80, y = -35 and z = -45, Determine the value of [(x³ + y³ + z³)/10³]
22% of ‘x’ is equal to 66% of ‘y’, then find the value of x: y.
If, 4x + y = 10, and 2xy = 8, and 4x > y, then find the value of 64x³ – y³.