Question
If 6y² – 13y + 6 = 0, then find the sum of the two
roots of the equation.Solution
6y² – 13y + 6=0 6y² – 4y-9y+6=0 2y(3y-2)-3(3y-2) =0 (2y-3) (3y-2) =0 When 2y-3=0 Y=3/2 And 3y-2=0 Then y=2/3 Product of roots =3/2+2/3 =13/6 Â
? = (597.98 ÷ (6.97 2.01 – 3.1)) × 12.9
1153, 1206, ?, 1326, 1393, 1464
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