Question
If x2a = y2b =z2c ≠
0 and x2 = yz, then the value of (ab + bc + ca) /bc is :Solution
x 2a =y2b =z2c =k x 2a =k x =(k)2a y =(k)1/2b z =(k) 1/2b x 2 =yz ((k) 1/2b )2=(k) 1/2b (k) 1/2b (k) 1/a = (k) 1/2b + 1/2b 1/a = 1/2b + 1/2c By adding 1/2a both sides, 1/a +1/ 2a =1/ 2a +1/ 2b +1/ 2c 3/2a = (ab + bc + ac) /2abc (ab + bc + ac) /bc = 3
More Algebra Questions
cot 13˚
cot 14˚ ...If sin θ + cos θ = 1.2, find the value of sin θ. cos θ.
If tan A = 1, then what will be the value of sec² A + cosec² A?
2 × Tan 30° / (1 + Tan2 30°) equals:
- If sin (4A − B) = (√2/2) and cos (A + B) = (√2/2), where 0° < A, B < 90°, then find the value of ‘A’.
Find the Value of Sin⁶`Theta` + Cos⁶`Theta` + 3Sin² `theta` Cos²`Theta`
If sin(3θ) = cos(2θ), then find the value of θ between 0 and 90 degrees.
cos (sec-1 x) is equal to –
Find the value of sin 240 °
Relevant for Exams:
