Question
If x2a = y2b =z2c ≠
0 and x2 = yz, then the value of (ab + bc + ca) /bc is :Solution
x 2a =y2b =z2c =k x 2a =k x =(k)2a y =(k)1/2b z =(k) 1/2b x 2 =yz ((k) 1/2b )2=(k) 1/2b (k) 1/2b (k) 1/a = (k) 1/2b + 1/2b 1/a = 1/2b + 1/2c By adding 1/2a both sides, 1/a +1/ 2a =1/ 2a +1/ 2b +1/ 2c 3/2a = (ab + bc + ac) /2abc (ab + bc + ac) /bc = 3
(22 × 52 ) + 4 × 6 = ? - √324
What should come in place of (?) question mark in the given expression.
 (25% of 320) + (3/8 of 400) − 30 = ?
(5832)1/3  × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 ÷ 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 ÷ 12) × 5 } − (18 ÷ 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 ÷ 7)
464 + 181 +? = (154 × 25) - (15) 2 Â
15% of 1800 + 22 = ?Â
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