Question
One year ago from now, the ages of 'A' and 'B' were in the ratio 3:2, respectively. Six years ago from now, the ages of 'A' and 'B' were in the ratio 2:1. Present age of 'A' is how much percent more than that of 'B'?
Solution
Let the ages of 'A' and 'B', 6 years ago from now was, '2x' years and 'x' years, respectively. ATQ; {(2x + 5)/(x + 5)} = (3/2) Or, 2 X (2x + 5) = 3 X (x + 5) Or, 4x + 10 = 3x + 15 Or, x = 5 So, present age of 'A' = 2 X 5 + 6 = 16 years And present age of 'B' = 5 + 6 = 11 years So, required percentage = {(16 - 11)/11} X 100 = 45.45%
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