Question
Two years hence, the ratio of the ages of βBβ and
βCβ will be 5:4. The present age of βCβ is half of the sum of the present ages of βAβ and βBβ. Three years ago, the product of the ages of βAβ and βCβ (in years) was 77. If the age of βBβ eight years hence from now will be βpβ years, then how many statement(s) among the following is/are true about βpβ? Statement I: βpβ is a perfect square. Statement II: (p β 2) is a prime number. Statement III: (p + 3) is completely divisible by 6. Statement IV: (p + 5) > 28Solution
Let the ages of βBβ and βCβ two years hence from now be β5kβ years and β4kβ years respectively. Present age of βBβ = (5k β 2) years Present age of βCβ = (4k β 2) years So, present age of βAβ = 2 Γ (4k β 2) β (5k β 2) = (3k β 2) years Now, (3k β 2 β 3) Γ (4k β 2 β 3) = 77 Or, (3k β 5) Γ (4k β 5) = 77 Or, 12kΒ² β 15k β 20k + 25 = 77 Or, 12kΒ² β 35k β 52 = 0 Or, (12k + 13)(k β 4) = 0 So, βkβ = β(13/12) or βkβ = 4 But βkβ cannot be negative. So, βkβ = 4 Therefore, βpβ = (5k β 2) + 8 = 5k + 6 = 26 Statement I 26 is not a perfect square.
So, statement I is false. Statement II 26 β 2 = 24, which is not prime.
So, statement II is false. Statement III 26 + 3 = 29, which is not completely divisible by 6.
So, statement III is false. Statement IV 26 + 5 = 31 > 28.
So, statement IV is true. Therefore, one among the four statements given is true. Hence, option E.
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