Question
The present ages of A and B are in the ratio 11:9. The
ratio of A’s age 10 years hence to B’s age 18 years ago is 3:1. If C is 20% less than the sum of the present ages of A and B, find C’s age now.Solution
ATQ, Let present ages of A and B be 11x and 9x years. (11x + 10)/(9x - 18) = 3/1 ⇒ 11x + 10 = 27x - 54 ⇒ 16x = 64 ⇒ x = 4 Sum = 11x + 9x = 20x = 80 Therefore, C = 0.80 × 80 = 64 years
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