Question
The present age of A is 4 years more than the present
age of B. 5 years ago, A's age was twice that of B. What are the present ages of A and B?Solution
Let the present age of B be x. Then, the present age of A = x + 4. 5 years ago, A's age = (x + 4) - 5 = x - 1, and B's age = x - 5. We are told that 5 years ago, A’s age was twice that of B’s age: x - 1 = 2(x - 5) Simplify and solve: x - 1 = 2x - 10 -1 + 10 = 2x - x 9 = x So, the present age of B is 9, and the present age of A is x + 4 = 13. Correct Option: b
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