Question
The present age of a father is three times that of his
son. After 10 years, the father’s age will be twice that of his son. What are their current ages?Solution
Let son’s age = x, and father’s age = 3x. After 10 years, father’s age = 3x + 10, and son’s age = x + 10. (3x + 10) = 2(x + 10) Solving for x, x = 10. Father’s age = 3(10) = 30, Son’s age = 10. Correct Option: a) Father: 30, Son: 10
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