Question
The current ages of individuals 'A', 'B', and 'C' are in
the proportion 7:2:3. Eight years prior, the average age of the three was 28 years. Determine the age of 'B' four years hence from today.Solution
Let the present ages of 'A', 'B' and 'C' be '7x', '2x' and '3x' years, respectively. Average of present ages = {7x + 2x + 3x} Ă· 3 = '4x' years ATQ; {(7x - 8) + (2x - 8) + (3x - 8) } Ă· 3 = 28 Or, 12x - 24 = 28 X 3 Or, 12x = 84 + 24 So, 'x' = (108/12) = 9 Therefore, age of 'B' 4 years hence from now = (2x + 4) years = 2 x 9 + 4 = 22 years
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