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    Question

    The current ages of individuals 'A', 'B', and 'C' are in

    the proportion 7:2:3. Eight years prior, the average age of the three was 28 years. Determine the age of 'B' four years hence from today.
    A 22 years Correct Answer Incorrect Answer
    B 24 years Correct Answer Incorrect Answer
    C 18 years Correct Answer Incorrect Answer
    D 20 years Correct Answer Incorrect Answer
    E 30 years Correct Answer Incorrect Answer

    Solution

    Let the present ages of 'A', 'B' and 'C' be '7x', '2x' and '3x' years, respectively. Average of present ages = {7x + 2x + 3x} ÷ 3 = '4x' years ATQ; {(7x - 8) + (2x - 8) + (3x - 8) } ÷ 3 = 28 Or, 12x - 24 = 28 X 3 Or, 12x = 84 + 24 So, 'x' = (108/12) = 9 Therefore, age of 'B' 4 years hence from now = (2x + 4) years = 2 x 9 + 4 = 22 years

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