Question
Present ages of 'X' and 'Y' are in ratio 7:8,
respectively. If twelve years hence from now, age of 'X' will be 15% less than that of 'Y', then find the ratio of present ages of 'X' and 'Z' given that 'Z' is 9 years older than 'X'.Solution
ATQ, Let the present ages of 'X' and 'Y' be '7x' years and '8x' years, respectively. So, (7x + 12) = (8x + 12) X 0.85 Or, 7x + 12 = 6.8x + 10.2 Or, 0.2x = 1.8 So, x = 9 So, present age of 'X' = 7x = 7 X 9 = 63 years And present age of 'Z' = 63 + 9 = 72 years So, required ratio = 63:72 = 7:8
(?)2 + 9.113 = 31.92 – 39.03
739.85 + 5003 ÷ 24.99 × 69.999 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value....
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(155.34 + 234.78) ÷ 12.65 = ? ÷ 4.99
(899.117 + 1.1121) X 72.731 = ? + 49.95 X 64.78 + 29.50
? = 28.04² ÷ (4.01⁵ + 9.89 × 20.20) + 84.56% of (198.76 × 30.03)
179.89 + 17.04² + ?³ = √783.97 * 29.09
