Question
The ratio of the present age of 'I' to that of 'J' is
7:9. If eight years hence, the ratio of their ages will become 9:11, find the sum of their ages, eight years ago from now.Solution
ATQ, Let the present ages of 'I' and 'J' be '7m' years and '9m' years, respectively. ATQ, (7m+8)/(9m+8) = 9/11 ​Or, 11×(7m+8)=9×(9m+8) Or, 77m+88=81m+72 Or, 81m−77m=88−72 So, 4m = 16 So, m= (16/4) = 4 Present age of 'I' = 7m = 7 × 4 = 28 years Present age of 'J' = 9m = 9 × 4 = 36 years Required sum = (28 - 8) + (36 - 8) = 20 + 28 = 48 years
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
45.05% of 260.05 – 20.15% of 149.99 × 3.02 = ?
14, 27, 40, 53, 67, 79Â
(48/16)2 × 50/50 ÷ 50/800 = ? Â
1726 1/3 + 40% of 1849.889 + 15.12 × 18.25 = ?
(74.76 ÷ 12.11 X ?)% of 239.89 = 600.19
14.99% of 7820 + 5535.25 ÷ 123.001 - ? = 84
Direction: Please solve the following expression and choose the closest option
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
63.981 + 64.001 + 65.08019 + 63.11112 =?
