The ratio of age of ‘B’ after 5 years from now and age of ‘C’ 4 years ago from now is 7:4, respectively. The present age of ‘C’ is 40% of the present age of ‘A’. If present age of ‘A’ is 50 years then find the present age of ‘B’.
Present age of ‘C’ = 0.4 × 50 = 20 years 4 years ago from now, age of ‘C’ = 20 – 4 = 16 years 5 years hence from now, age of ‘B’ = 16 × (7/4) = 28 years Present age of ‘B’ = 28 – 5 = 23 years
I. 2x2 + 3x - 9 = 0
II. 3y2 - y - 10 = 0
I. 6x² - 49x + 99 = 0
II. 5y² + 17y + 14 = 0
I. 2y² - 11 y + 15 = 0
II. 2x² + 3x – 14 = 0
I. 5x2 – 7x – 6 =0
II. 2y2 – 5y – 7 =0
I. 15y2+ 26y + 8 = 0
II. 20x2+ 7x – 6 = 0
If a quadratic polynomial y = ax2 + bx + c intersects x axis at a and β, then
I. 35 y² + 58 y + 24 = 0
II. 21 x² + 37 x + 12 = 0
I. 2x2 – 10x – 48 = 0
II. y2 – 16y – 297 = 0
I. x2-2x- √5x+2√5 = 0
II. y2-√3 y- √2 y+ √6 = 0
...I. 7x² + 52x + 21 = 0
II. 6y² + 7y - 24 = 0
