Question
12 years ago from now, ratio of ages of βRβ and
βLβ was 3:5, respectively. If βLβ is 8 years elder to βRβ, then what will be the age of βLβ, 4 years hence from now?Solution
Let present ages be: R = r, L = l Given: L is 8 years older than R l = r + 8 12 years ago: (r β 12) : (l β 12) = 3 : 5 (r β 12)/(l β 12) = 3/5 5(r β 12) = 3(l β 12) 5r β 60 = 3[(r + 8) β 12] 5r β 60 = 3(r β 4) 5r β 60 = 3r β 12 2r = 48 r = 24 l = r + 8 = 24 + 8 = 32 Lβs age 4 years hence = 32 + 4 = 36
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