Question
12 years ago from now, ratio of ages of ‘R’ and
‘L’ was 3:5, respectively. If ‘L’ is 8 years elder to ‘R’, then what will be the age of ‘L’, 4 years hence from now?Solution
Let present ages be: R = r, L = l Given: L is 8 years older than R l = r + 8 12 years ago: (r − 12) : (l − 12) = 3 : 5 (r − 12)/(l − 12) = 3/5 5(r − 12) = 3(l − 12) 5r − 60 = 3[(r + 8) − 12] 5r − 60 = 3(r − 4) 5r − 60 = 3r − 12 2r = 48 r = 24 l = r + 8 = 24 + 8 = 32 L’s age 4 years hence = 32 + 4 = 36
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