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    Question

    12 years ago from now, ratio of ages of β€˜R’ and

    β€˜L’ was 3:5, respectively. If β€˜L’ is 8 years elder to β€˜R’, then what will be the age of β€˜L’, 4 years hence from now?
    A 45 years Correct Answer Incorrect Answer
    B 49 years Correct Answer Incorrect Answer
    C 36 years Correct Answer Incorrect Answer
    D 40 years Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let present ages be: R = r, L = l Given: L is 8 years older than R l = r + 8 12 years ago: (r βˆ’ 12) : (l βˆ’ 12) = 3 : 5 (r βˆ’ 12)/(l βˆ’ 12) = 3/5 5(r βˆ’ 12) = 3(l βˆ’ 12) 5r βˆ’ 60 = 3[(r + 8) βˆ’ 12] 5r βˆ’ 60 = 3(r βˆ’ 4) 5r βˆ’ 60 = 3r βˆ’ 12 2r = 48 r = 24 l = r + 8 = 24 + 8 = 32 L’s age 4 years hence = 32 + 4 = 36

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