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    Question

    Present ages of ‘A’, ‘B’ and ‘C’ are in the

    ratio 8:10:11, respectively. If present average age of ‘A’ and ‘C’ is 19 years, then find the age of ‘B’ when ‘C’ was 20 years old?
    A 18 years Correct Answer Incorrect Answer
    B 14 years Correct Answer Incorrect Answer
    C 17 years Correct Answer Incorrect Answer
    D 12 years Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let the present ages of ‘A’, ‘B’ and ‘C’ be ‘8x’ years, ‘10x’ years and ‘11x’ years, respectively. ATQ; (11x + 8x) ÷ 2 = 19 Or, 19x = 38 So, x = 2 So, present age of ‘C’ = 11 × 2 = 22 years Present age of ‘B’ = 10 × 2 = 20 years Difference between the ages of ‘B’ and ‘C’ = 22 – 20 = 2 years So, age of ‘B’ when ‘C’ was 24 years old = 20 – 2 = 18 years

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