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Start learning 50% faster. Sign in nowLet the present ages of ‘A’, ‘B’ and ‘C’ be ‘8x’ years, ‘10x’ years and ‘11x’ years, respectively. ATQ; (11x + 8x) ÷ 2 = 19 Or, 19x = 38 So, x = 2 So, present age of ‘C’ = 11 × 2 = 22 years Present age of ‘B’ = 10 × 2 = 20 years Difference between the ages of ‘B’ and ‘C’ = 22 – 20 = 2 years So, age of ‘B’ when ‘C’ was 24 years old = 20 – 2 = 18 years
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