Question
Present ages of βAβ, βBβ and βCβ are in the
ratio 8:10:11, respectively. If present average age of βAβ and βCβ is 19 years, then find the age of βBβ when βCβ was 20 years old?Solution
Let the present ages of βAβ, βBβ and βCβ be β8xβ years, β10xβ years and β11xβ years, respectively. ATQ; (11x + 8x) Γ· 2 = 19 Or, 19x = 38 So, x = 2 So, present age of βCβ = 11 Γ 2 = 22 years Present age of βBβ = 10 Γ 2 = 20 years Difference between the ages of βBβ and βCβ = 22 β 20 = 2 years So, age of βBβ when βCβ was 24 years old = 20 β 2 = 18 years
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