Question
Present average age of 4 friends: ‘A’, ‘B’,
‘C’ and ‘D’ is 24 years. If their ages are in the arithmetic progression in the same order and ‘D’ is 4 years older than ‘B’, then find the sum of present ages of ‘A’ and ‘C’.Solution
Common difference between ages = (4/2) = 2 years. So, let present ages of ‘A’, ‘B’, ‘C’ and ‘D’ be ‘x’, (x + 2) years, (x + 4) years and (x + 6) years, respectively According to question: x + x + 2 + x + 4 + x + 6 = 96 Or, 4x = 84 Or, x = 21 years (Age of A) Present age of ‘C’ = x + 4 = 21 + 4 = 25 years Required sum = 21 + 25 = 46 years
11 46 109 208 351 ?
200, 50, ‘?’, 46.875, 82.03125
3 15 35 63 99 ?
To find the Next number in the given series.
342 510 726 996 1326 ?
...12, 20, 36, ?, 132, 260
13 182 303 384 433 ?
...13 14 22.5 ? 120 363
...3, 2, 3, 8, 31, ?
Direction: Which of the following will replace ‘?’ in the given question?
2, ‘?’, 46, 136, 311, 605, 1086
24 25 46 ? 572 2885
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