Question
Present average age of 4 friends: ‘A’, ‘B’,
‘C’ and ‘D’ is 24 years. If their ages are in the arithmetic progression in the same order and ‘D’ is 4 years older than ‘B’, then find the sum of present ages of ‘A’ and ‘C’.Solution
Common difference between ages = (4/2) = 2 years. So, let present ages of ‘A’, ‘B’, ‘C’ and ‘D’ be ‘x’, (x + 2) years, (x + 4) years and (x + 6) years, respectively According to question: x + x + 2 + x + 4 + x + 6 = 96 Or, 4x = 84 Or, x = 21 years (Age of A) Present age of ‘C’ = x + 4 = 21 + 4 = 25 years Required sum = 21 + 25 = 46 years
Statements: X & C, C % W, W $ S, S @ L
Conclusions: I. L & C II. S # C III. W @ X
...In the question assuming the given statements to be true, find which of the conclusion(s) among given three conclusions is/are definitely follows and ...
In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is /are definitely true and t...
In the following question, a relationship between different elements is shown in the statements, followed by two conclusions I and II. Assuming the stat...
Given the following expression, find which of the equations from the given options is true ?
N ≥ P ≥ M ≥ U = D ≥ F
Statements:K < L,L ≥ M,M > N
Conclusions: I. K < M II. N > K
Statements: F @ R, R $ J, V % J, V # Z
Conclusions: I. F * V       II. R * V                              �...
Statements: H ≥ I < J ≥ K > L ≥ M
Conclusions:
I. L < J
II. M ≤ J
III. K ≥ J
IV. I = K
Statements: P < R = S = T < U < V; Q = V < W < X < O
Conclusions:
I. Q > R
II. P < OStatements: T = U > W < X ≤ Y ≥ V > Z > R = S
Conclusions:
I. T > V
II. T ≤ V
III. S > Y
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