Question
Present age of βAβ is 30% more than that of βBβ.
If 8 years hence from now, βBβ will be 9 years younger than βAβ, then find the sum of present ages of βAβ and βBβ.Solution
Let present age of βBβ be βxβ years Present age of βAβ = x Γ 1.3 = β1.3xβ years ATQ; (x + 8) + 9 = (1.3x + 8) Or, x + 17 = 1.3x + 8 Or, 9 = 0.3x Or, x = 30 So, present age of βBβ = 30 years And, present age of βAβ = 30 + 9 = 39 years Required sum = 39 + 30 = 69 years
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