Question
The ratio of the present ages of father and his son is
8:3. The product of their ages 3 years ago was 29 times of his son’s age that year. What was son’s age 2 year ago?Solution
Let present age of father and son be 8x and 3x respectively. According to question,  => (8x – 3) (3x – 3) = 29 × (3x – 3)  => (8x – 3) = 29 => 8x = 32 => x = 4 Therefore, son’s age 2 years ago = (3x – 2) = 10 years
More Age Questions
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04Â
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?
