Question
The ratio of the present ages of ‘A’ and ‘B’ is
3:2, respectively. Four years hence from now, the age of ‘B’ will be 20 years. If the average of present ages of ‘A’, ‘B’ and ‘C’ is 25 years, then find the present age of ‘C’.Solution
Let the present ages of ‘A’ and ‘B’ be 3x years and 2x years, respectively Therefore, 2x + 4 = 20 Or, 2x = 16 Or, x = 8 Sum of present ages of ‘A’ and ‘B’ = 3x + 2x = 40 years Sum of present ages of ‘A’, 'B’ and ‘C’ = 25 × 3 = 75 years Therefore, present age of ‘C’ = 75 – 40 = 35 years
Evaluate: 360 ÷ [ {18 − (6×2)} × 5 ] + 72 − 33
(43)² - (28)² + (32)² = ?% of 2500
Evaluate:
√729 + √49 - √16 + 1/√64
What will come in place of (?) in the given expression.
12.5 + 7.75 - 3.6 = ?62 of 8 - 320 ÷ 4 = ?3 + 200
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)
What will come in the place of question mark (?) in the given expression?
30% of 520 + 16% of 1500 = ? + 244
60% of 120 – ?% of 64 = 20% of 200
35% of 840 + 162 = ? – 25% × 300
20% of 240 + 18% of 200 = ?
