Question
The ratio between the present age of Beena and Meenal is
4:5, where Sumit is 3 years younger than Meenal then find the ratio of their ages 6 years hence.Solution
Let present age of Beena be 4x years and of Meenal of 5x years. According to the question, => 4x = 5x – 3 => x = 3 Present age of Beena = 4 × 3 = 12 years Present age of Meenal = 5 × 3 = 15 years Now, 6 years hence their ratio of ages, Beena age = 12 + 6 = 18 years Meenal age = 15 + 6 = 21 years Required ratio = 18:21 = 6:7
41.66% of 888 + 66.66% of 1176 = ?2 - 4√ 16 Â
Evaluate: 320 − {18 + 4 × (21 − 9)}
Simplify: 72 ÷ 6 × 3 − 8 + 4
118 × 6 + 13 + 83 = ?
Simplify the following expression:
  (400 +175) ² - (400 – 175) ² / (400 × 175)
150% of 850 ÷ 25 – 25 = ?% of (39312 ÷ 1512)
(75 + 0.25 × 10) × 4 = ?2 - 14
26% of 650 + 15% of 660 – 26% of 450 = ?
115% of 40 + 3 × 4 = ? × 11 – 8