Question

Using the Banker's Algorithm with Available=(3,3,2) and Need: P0(7,4,3), P1(1,2,2), P2(6,0,0), P3(0,1,1), P4(4,3,1) (Allocations: P0(0,1,0), P1(2,0,0), P2(3,0,2), P3(2,1,1), P4(0,0,2)), which of the following is a valid safe sequence?

A P0, P1, P2, P3, P4
B P0, P2, P1, P3, P4
C P1, P3, P4, P0, P2
D P4, P2, P0, P1, P3
E P2, P0, P1, P3, P4
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