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      Question

      Trace the execution of the following Java code:

          public class Flow {         public static void main(String[] args) {             int count = 0;             for (int i = 0; i < 2; i++) {                 for (int j = 0; j < 3; j++) {                     count++;                 }             }             System.out.println(count);         }     }     What is the output?
      B 2 Correct Answer Incorrect Answer
      C 3 Correct Answer Incorrect Answer
      D 5 Correct Answer Incorrect Answer
      E 6 Correct Answer Incorrect Answer

      Solution

      The outer loop runs for i = 0 and i = 1 (2 iterations).     The inner loop runs for j = 0, 1, 2 (3 iterations) for *each* iteration of the outer loop.     So, count++ executes 2 * 3 = 6 times.     Initial count = 0. After 6 increments, count = 6.

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