Question
A circuit has five branches with four nodes including
reference node , then the number of linearly independent mesh equation would be_______Solution
We use the relationship between branches (B), nodes (N), and meshes (M). The number of independent mesh equations is given by: M = B β N + 1 Here, B = 5 (branches) N = 4 (nodes, including reference) So, M = 5 β 4 + 1 = 2
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