Question
Find the equivalent resistance when three resistors of 4
Ω, 6 Ω, and 12 Ω are connected in parallel.Solution
1/R = 1/R₁ + 1/R₂ + 1/R₃ = 1/4 + 1/6 + 1/12 = (3 + 2 + 1) / 12 = 6/12 = 1/2 R = 2 Ω
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