Question
The time period of a second’s pendulum is –
Solution
A seconds pendulum is a pendulum whose period is precisely two seconds; one second for a swing in one direction and one second for the return swing, a frequency of 1/2 Hz. At standard gravity its length is 0.994 m.
1(1/2)+ 11(1/3) + 111(1/2) + 1111(1/3) + 11111(1/2) = ?
25% of 250 + 32% of 200 = ? ÷ √ 16
√4761 ÷ 23 + √12769 = ? × 58
(3984 ÷ 24) x (5862 ÷ 40) = ?
√256 * 3 – 15% of 300 + ? = 150% of 160
What will come in the place of question mark (?) in the given expression?
? = ((180 × 27) ÷ 60) + ((52 × 70) ÷ (13 × 280))3
...(342 – 20% of 5280) = ? ÷ 3
40% of 50 + 50% of ? = 25% of 300 - 10% of 250
(22.5 × 24) ÷ 40 + 51.50 = ? ÷ 5.25
√ 729 × 5 – 220 % of 15 + ? = 120% of 160