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Start learning 50% faster. Sign in nowGiven, Distance of the object from the lens = u = -10 cm Refractive index of the lens = µ = 1.5 Radii of curvature of the lens are 30 cm in magnitude R1 = 30 cm and R2 = -30 cm (As per sign convention) According to Len's Maker's formula 1/f = (µ - 1)(1/R1 - 1/R2) = (1.5 - 1)(1/30 - (-1/30) = 0.5 x 2/30 = 1/30 or, f = 30 cm From lens equation, 1/v - 1/u = 1/f v = fu/(u + f) = (30 x -10)/(-10 + 30) = -300/20 = -15 cm The image is formed 15 cm on the same side as the object
3/7 of 686 + 133(1/3)% of 33 – 69 =?
961 × 4 ÷ 31 – 15% of 180 = ? – 73
The value of (40 + 3/4 of 32) /[37 + 3/4 of (34-6)] is:
(? + 16) × 12 + 25% of 840 = 252 + 5
144 (1/2) × 14 – 28 = 7 × ?
22 + 60 × 3 ÷ 12 = ?
Solve the following:
523 + 523 x 523 ÷ 523