An object is placed at a distance of 10 cm in front of a

Solution

Given, Distance of the object from the lens = u = -10 cm Refractive index of the lens = µ = 1.5 Radii of curvature of the lens are 30 cm in magnitude R1 = 30 cm and R2 = -30 cm (As per sign convention) According to Len's Maker's formula 1/f = (µ - 1)(1/R1 - 1/R2) = (1.5 - 1)(1/30 - (-1/30) = 0.5 x 2/30 = 1/30 or, f = 30 cm From lens equation, 1/v - 1/u = 1/f v = fu/(u + f) = (30 x -10)/(-10 + 30) = -300/20 = -15 cm The image is formed 15 cm on the same side as the object