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    Question

    A 4 cm wire carrying a current of 15 A is placed inside

    a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?
    A 16.2 Γ— 10^βˆ’2 N Correct Answer Incorrect Answer
    B 3.1 Γ— 10^βˆ’3 N Correct Answer Incorrect Answer
    C 8.1 Γ— 10^βˆ’2 N Correct Answer Incorrect Answer
    D 3.1 Γ— 10^βˆ’5 N Correct Answer Incorrect Answer

    Solution

    i=15 A, l=4cm=0.04m, B=0.27T and ΞΈ=90 ∘ Magnetic force on a current carrying conductor is given by: β†’F=i(β†’lΓ—β†’B)=ilBsinΞΈ F=15Γ—0.04Γ—0.27Γ—sin90 ∘ F=16.2Γ—10βˆ’2N

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