Question
A current-carrying conductor is placed perpendicular to
a uniform magnetic field. The force on the conductor is given by:Solution
The force on a current-carrying conductor in a magnetic field is given by: F=BILsinθ For a conductor placed perpendicular to the field, θ=90∘, so sin 90° = 1, and F=BIL.
A bought an article at 20% less of the marked price and sold it at 25% more than the marked price. Find the profit earned by him.
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A trader bought some orange at 7 for Rs 11. He sold all at 2 for Rs 3. Thereby he losses Rs 30. Find number of oranges sold.
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