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focal length f = -15 cm Distance of object u = -30 cm 1/ v = 1/f +1/u substituting these values in the lens equation we get, 1/v =1/-15 +1/-30 1/v =-3/30 v = -10cm Hence, the distance of the object from the lens is 10 cm and the negative sign signifies a virtual image.
54 × 70 × 33 × 42 =
If 2x = 3y = 6-z, then (1/x) + (1/y) + (1/z) =?
(1.69) -1.5 = ?
Find the value of 56× 59÷ 514= ?
(0.64) -1.5 = ?
What will come in place of a?
(6)1.2 × (216 )2.7 × (36)2.7 = 6a
If (9000) 5 = 59.049
Find the Value of √(-√3+√(3+8√(7+4√3)))?
(537824) -3/5 = ?
(0.64)3/2 = ?