Sum of squares of three consecutive numbers is 974. Find the sum of first and third number.
Let the numbers be (x – 1), x and (x + 1) => (x – 1)2+ x2+ (x + 1)2= 974 => x2– 2x + 1 + x2+ x2+ 2x + 1 = 974 => 3x2= 974- 2 => x2= 972/3 => x2= 324 => x = 18 Required sum = (18 – 1) + (18 + 1) = 36
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