Question
Reena reaches a birthday party 20 min late if she walks
3 km/h from her house. If she increases her speed to 4 km/h she would reach 30 min early, then the distance between her house and the venue of the birthday party is:Solution
Let the distance = D km. Time at 3 km/h = D/3, time at 4 km/h = D/4. Total time difference = 20+30=50 minutes = 5/6 hours. 
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