Question
The mean of 36 numbers was found as 42. Later on, it was
determined that a number 47 was misread as 41. Find the correct mean of the given numbers (rounded off to two places of decimal).Solution
ATQ, The original sum of the numbers was 42×36 =1512. The number 47 was misread as 41, so the sum is 6 less than it should be. To correct it, add 6 to the sum: 1512+6 = 1518. Divide the corrected sum by 36 to find the new mean: 1518÷36 = 42.17. So, the correct mean is 42.17.
In the figure BD = CD = AC, ∠ABC = 27 ° , ∠ACD = y. Find value of x.
In an obtuse angle  triangle PQR, the external angle bisector of angle P intersect the extended part of line RQ at M and the external angle bisector...
The lengths of three medians in a triangles are 9 cm, 12 cm, 15 cm. What is the area of that traingle (in cm 2 )?
If G is the centroid and AD, BE, CF are three medians of ∆ABC with area 54 cm 2 , then the area of ∆BGD is?
The length of the each side of an equilateral triangle is 14√3. The area of incircle, (cm 2 ) is
The perimeter of a rectangle is 48 cm, and the ratio of its length to breadth is 3:5. What is the area of the rectangle?
Find area of a sector of radius 14 cm with central angle 90°. (π = 22/7)
From an external point P, two tangents PR and PS are drawn to a circle with a radius of 10 cm. If the length of each tangent is 14 cm, determine the per...
If in a ΔABC, D is a point on BC such that BD = 1cm , BC = 3 cm then what is ratio of area of ΔABD to area of ΔADC ?