x2 − x + 1 = 0 αβ = 1 α + β =1 cubing on both sides α3 + β3 + 3αβ(α + β) = 1 α3 + β3 + 3 ∗ 1(1 ) = 1 α3 + β3 = -2 α3 β3 = 1 Sum of the roots=-2 product=1 Required equation is x2 + 2x + 1 = 0
Statements: N # L, L @A, A % I, I & E
Conclusions :
I.E $ L <...
Statement: D < F; D ≥ E > G; I ≥ H > F
Conclusion:
I. G ≥ F
II. H ≥ D
Statements: I < G = Z = X ≤ A ≤ R < N > D = V
Conclusions:
I. I > D
II. R ≥ G
III. X < V
Statements: S > P = N ≥ G; Y = G ≥ J < O
Conclusions:
I. P ≥ J
II. J < P
Statements: Y ≤ A = F; H > T; H < V < F; Y ≤ W < R
Conclusions:
I. Y < V
II. T < A
III. W > H
Statements: N & C, C # I, I @ L, L % Y
Conclusions: I. C & Y II. L # N
...Statements: T < I = Q < U ≤ V; U > F; J = U ≤ E
Conclusions:
I. E > Q
II. V ≥ T
III. T < V
IV. F = ...
Statements: A ≥ M > E, K ≤ J ≤ D = E, B ≤ Z ≤ Y = K
Conclusion:
I. M > Y
II. D ≥ B
Statements: A @ Z, Z # L, L % N, N @ U
Conclusions:
I. A @ N
II. Z @ U
III. A # L
Which one the following symbols should replace the question mark in the given expression, in order to make the expressions L ≤ I as well as N > K ...
